Solve 8^2*5^2+85+4/8+3

$${ 8 }^{ 2 } \times { 5 }^{ 2 } +85+ \frac{ 4 }{ 8+3 }$$

Evaluate

$$\frac{18539}{11}\approx 1685.363636364$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$64\times 5^{2}+85+\frac{4}{8+3}$$

Calculate 5 to the power of 2 and get 25.

$$64\times 25+85+\frac{4}{8+3}$$

Multiply 64 and 25 to get 1600.

$$1600+85+\frac{4}{8+3}$$

Add 1600 and 85 to get 1685.

$$1685+\frac{4}{8+3}$$

Add 8 and 3 to get 11.

$$1685+\frac{4}{11}$$

Convert 1685 to fraction \frac{18535}{11}.

$$\frac{18535}{11}+\frac{4}{11}$$

Since \frac{18535}{11} and \frac{4}{11} have the same denominator, add them by adding their numerators.

$$\frac{18535+4}{11}$$

Add 18535 and 4 to get 18539.

$$\frac{18539}{11}$$

Factor

$$\frac{18539}{11} = 1685\frac{4}{11} = 1685.3636363636363$$