Solve 7^27^2*5^2-27^2=

$${ 7 }^{ 2 } { 7 }^{ 2 } \times { 5 }^{ 2 } - { 27 }^{ 2 } =$$

Evaluate

$$59296$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 2 to get 4.

$$7^{4}\times 5^{2}-27^{2}$$

Calculate 7 to the power of 4 and get 2401.

$$2401\times 5^{2}-27^{2}$$

Calculate 5 to the power of 2 and get 25.

$$2401\times 25-27^{2}$$

Multiply 2401 and 25 to get 60025.

$$60025-27^{2}$$

Calculate 27 to the power of 2 and get 729.

$$60025-729$$

Subtract 729 from 60025 to get 59296.

$$59296$$

Factor

$$2^{5}\times 17\times 109$$