Solve 4.5^2=4.5^2+x^2

$${ 4.5 }^{ 2 } = { 4.5 }^{ 2 } + { x }^{ 2 }$$

Solve for x

$$x=0$$

Steps by Finding Square Root

Calculate 4.5 to the power of 2 and get 20.25.

$$20.25=4.5^{2}+x^{2}$$

Calculate 4.5 to the power of 2 and get 20.25.

$$20.25=20.25+x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$20.25+x^{2}=20.25$$

Subtract 20.25 from both sides.

$$x^{2}=20.25-20.25$$

Subtract 20.25 from 20.25 to get 0.

$$x^{2}=0$$

Take the square root of both sides of the equation.

$$x=0 x=0$$

The equation is now solved. Solutions are the same.

$$x=0$$

Steps Using the Quadratic Formula

Calculate 4.5 to the power of 2 and get 20.25.

$$20.25=4.5^{2}+x^{2}$$

Calculate 4.5 to the power of 2 and get 20.25.

$$20.25=20.25+x^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$20.25+x^{2}=20.25$$

Subtract 20.25 from both sides.

$$20.25+x^{2}-20.25=0$$

Subtract 20.25 from 20.25 to get 0.

$$x^{2}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}}}{2}$$

Take the square root of 0^{2}.

$$x=\frac{0±0}{2}$$

Divide 0 by 2.

$$x=0$$