Solve 4^3+37^2/21-2^43+3^36/18-{2}^5+{3}^0

$${ 4 }^{ 3 } + \frac{ 3 { 7 }^{ 2 } }{ 21 } - { 2 }^{ 4 } 3+ \frac{ { 3 }^{ 3 } 6 }{ 18 } - { 2 }^{ 5 } + { 3 }^{ 0 }$$

Evaluate

$$1$$

Solution Steps

Calculate 4 to the power of 3 and get 64.

$$64+\frac{3\times 7^{2}}{21}-2^{4}\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Calculate 7 to the power of 2 and get 49.

$$64+\frac{3\times 49}{21}-2^{4}\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Multiply 3 and 49 to get 147.

$$64+\frac{147}{21}-2^{4}\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Divide 147 by 21 to get 7.

$$64+7-2^{4}\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Add 64 and 7 to get 71.

$$71-2^{4}\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Calculate 2 to the power of 4 and get 16.

$$71-16\times 3+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Multiply 16 and 3 to get 48.

$$71-48+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Subtract 48 from 71 to get 23.

$$23+\frac{3^{3}\times 6}{18}-2^{5}+3^{0}$$

Calculate 3 to the power of 3 and get 27.

$$23+\frac{27\times 6}{18}-2^{5}+3^{0}$$

Multiply 27 and 6 to get 162.

$$23+\frac{162}{18}-2^{5}+3^{0}$$

Divide 162 by 18 to get 9.

$$23+9-2^{5}+3^{0}$$

Add 23 and 9 to get 32.

$$32-2^{5}+3^{0}$$

Calculate 2 to the power of 5 and get 32.

$$32-32+3^{0}$$

Subtract 32 from 32 to get 0.

$$0+3^{0}$$

Calculate 3 to the power of 0 and get 1.

$$0+1$$

Add 0 and 1 to get 1.

$$1$$

Factor

$$1$$