Solve 4^2-4-2+{left(4/-2right)}^-2

$${ 4 }^{ 2 } -4-2+ { \left( \frac{ 4 }{ -2 } \right) }^{ -2 }$$

Evaluate

$$\frac{41}{4}=10.25$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$16-4-2+\left(\frac{4}{-2}\right)^{-2}$$

Subtract 4 from 16 to get 12.

$$12-2+\left(\frac{4}{-2}\right)^{-2}$$

Subtract 2 from 12 to get 10.

$$10+\left(\frac{4}{-2}\right)^{-2}$$

Divide 4 by -2 to get -2.

$$10+\left(-2\right)^{-2}$$

Calculate -2 to the power of -2 and get \frac{1}{4}.

$$10+\frac{1}{4}$$

Add 10 and \frac{1}{4} to get \frac{41}{4}.

$$\frac{41}{4}$$

Factor

$$\frac{41}{2 ^ {2}} = 10\frac{1}{4} = 10.25$$