Solve 4^2+3*6div963=x

$${ 4 }^{ 2 } +3 \times 6 \div 963=x$$

Solve for x

$$x = \frac{1714}{107} = 16\frac{2}{107} \approx 16.018691589$$

Steps for Solving Linear Equation

Calculate 4 to the power of 2 and get 16.

$$16+\frac{3\times 6}{963}=x$$

Multiply 3 and 6 to get 18.

$$16+\frac{18}{963}=x$$

Reduce the fraction \frac{18}{963} to lowest terms by extracting and canceling out 9.

$$16+\frac{2}{107}=x$$

Convert 16 to fraction \frac{1712}{107}.

$$\frac{1712}{107}+\frac{2}{107}=x$$

Since \frac{1712}{107} and \frac{2}{107} have the same denominator, add them by adding their numerators.

$$\frac{1712+2}{107}=x$$

Add 1712 and 2 to get 1714.

$$\frac{1714}{107}=x$$

Swap sides so that all variable terms are on the left hand side.

$$x=\frac{1714}{107}$$