Solve 332^2div6+293^2div5+201^2div3

$${ 332 }^{ 2 } \div 6+ { 293 }^{ 2 } \div 5+ { 201 }^{ 2 } \div 3$$

Evaluate

$$\frac{735112}{15}\approx 49007.466666667$$

Solution Steps

Calculate 332 to the power of 2 and get 110224.

$$\frac{110224}{6}+\frac{293^{2}}{5}+\frac{201^{2}}{3}$$

Reduce the fraction \frac{110224}{6} to lowest terms by extracting and canceling out 2.

$$\frac{55112}{3}+\frac{293^{2}}{5}+\frac{201^{2}}{3}$$

Calculate 293 to the power of 2 and get 85849.

$$\frac{55112}{3}+\frac{85849}{5}+\frac{201^{2}}{3}$$

Least common multiple of 3 and 5 is 15. Convert \frac{55112}{3} and \frac{85849}{5} to fractions with denominator 15.

$$\frac{275560}{15}+\frac{257547}{15}+\frac{201^{2}}{3}$$

Since \frac{275560}{15} and \frac{257547}{15} have the same denominator, add them by adding their numerators.

$$\frac{275560+257547}{15}+\frac{201^{2}}{3}$$

Add 275560 and 257547 to get 533107.

$$\frac{533107}{15}+\frac{201^{2}}{3}$$

Calculate 201 to the power of 2 and get 40401.

$$\frac{533107}{15}+\frac{40401}{3}$$

Divide 40401 by 3 to get 13467.

$$\frac{533107}{15}+13467$$

Convert 13467 to fraction \frac{202005}{15}.

$$\frac{533107}{15}+\frac{202005}{15}$$

Since \frac{533107}{15} and \frac{202005}{15} have the same denominator, add them by adding their numerators.

$$\frac{533107+202005}{15}$$

Add 533107 and 202005 to get 735112.

$$\frac{735112}{15}$$

Factor

$$\frac{2 ^ {3} \cdot 7 \cdot 13127}{3 \cdot 5} = 49007\frac{7}{15} = 49007.46666666667$$