Solve 3^2div2-25div5+7^2div7-8

$${ 3 }^{ 2 } \div 2-25 \div 5+ { 7 }^{ 2 } \div 7-8$$

Evaluate

$$-\frac{3}{2}=-1.5$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 2 to get 1.

$$\frac{3^{2}}{2}-\frac{25}{5}+7^{1}-8$$

Calculate 3 to the power of 2 and get 9.

$$\frac{9}{2}-\frac{25}{5}+7^{1}-8$$

Divide 25 by 5 to get 5.

$$\frac{9}{2}-5+7^{1}-8$$

Convert 5 to fraction \frac{10}{2}.

$$\frac{9}{2}-\frac{10}{2}+7^{1}-8$$

Since \frac{9}{2} and \frac{10}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-10}{2}+7^{1}-8$$

Subtract 10 from 9 to get -1.

$$-\frac{1}{2}+7^{1}-8$$

Calculate 7 to the power of 1 and get 7.

$$-\frac{1}{2}+7-8$$

Convert 7 to fraction \frac{14}{2}.

$$-\frac{1}{2}+\frac{14}{2}-8$$

Since -\frac{1}{2} and \frac{14}{2} have the same denominator, add them by adding their numerators.

$$\frac{-1+14}{2}-8$$

Add -1 and 14 to get 13.

$$\frac{13}{2}-8$$

Convert 8 to fraction \frac{16}{2}.

$$\frac{13}{2}-\frac{16}{2}$$

Since \frac{13}{2} and \frac{16}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{13-16}{2}$$

Subtract 16 from 13 to get -3.

$$-\frac{3}{2}$$

Factor

$$-\frac{3}{2} = -1\frac{1}{2} = -1.5$$