Solve 2003^3-2001^3-6*2003^2+24*2001

$${ 2003 }^{ 3 } - { 2001 }^{ 3 } -6 \times { 2003 }^{ 2 } +24 \times 2001$$

Evaluate

$$23996$$

Solution Steps

Calculate 2003 to the power of 3 and get 8036054027.

$$8036054027-2001^{3}-6\times 2003^{2}+24\times 2001$$

Calculate 2001 to the power of 3 and get 8012006001.

$$8036054027-8012006001-6\times 2003^{2}+24\times 2001$$

Subtract 8012006001 from 8036054027 to get 24048026.

$$24048026-6\times 2003^{2}+24\times 2001$$

Calculate 2003 to the power of 2 and get 4012009.

$$24048026-6\times 4012009+24\times 2001$$

Multiply 6 and 4012009 to get 24072054.

$$24048026-24072054+24\times 2001$$

Subtract 24072054 from 24048026 to get -24028.

$$-24028+24\times 2001$$

Multiply 24 and 2001 to get 48024.

$$-24028+48024$$

Add -24028 and 48024 to get 23996.

$$23996$$

Factor

$$2^{2}\times 7\times 857$$