Solve 2^2-6*2^2+2*9+2

$${ 2 }^{ 2 } -6 \times { 2 }^{ 2 } +2 \times 9+2$$

Evaluate

$$0$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$4-6\times 2^{2}+2\times 9+2$$

Calculate 2 to the power of 2 and get 4.

$$4-6\times 4+2\times 9+2$$

Multiply 6 and 4 to get 24.

$$4-24+2\times 9+2$$

Subtract 24 from 4 to get -20.

$$-20+2\times 9+2$$

Multiply 2 and 9 to get 18.

$$-20+18+2$$

Add -20 and 18 to get -2.

$$-2+2$$

Add -2 and 2 to get 0.

$$0$$

Factor

$$0$$