Solve 2^2+9y-8

$${ 2 }^{ 2 } +9y-8$$

Evaluate

$$9y-4$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$4+9y-8$$

Subtract 8 from 4 to get -4.

$$-4+9y$$

Differentiate w.r.t. y

$$9$$

Steps Using Derivative Rule for Sum

Calculate 2 to the power of 2 and get 4.

$$\frac{\mathrm{d}}{\mathrm{d}y}(4+9y-8)$$

Subtract 8 from 4 to get -4.

$$\frac{\mathrm{d}}{\mathrm{d}y}(-4+9y)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$9y^{1-1}$$

Subtract 1 from 1.

$$9y^{0}$$

For any term t except 0, t^{0}=1.

$$9\times 1$$

For any term t, t\times 1=t and 1t=t.

$$9$$