Solve 2^2+2(4)(2)+4^2

$${ 2 }^{ 2 } +2(4)(2)+ { 4 }^{ 2 }$$

Evaluate

$$36$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$4+2\times 4\times 2+4^{2}$$

Multiply 2 and 4 to get 8.

$$4+8\times 2+4^{2}$$

Multiply 8 and 2 to get 16.

$$4+16+4^{2}$$

Add 4 and 16 to get 20.

$$20+4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$20+16$$

Add 20 and 16 to get 36.

$$36$$

Factor

$$2^{2}\times 3^{2}$$