Solve 2^-2+{27}^frac{2{3}}+5^0+1/4

$${ 2 }^{ -2 } + { 27 }^{ \frac{ 2 }{ 3 } } + { 5 }^{ 0 } + \frac{ 1 }{ 4 }$$

Evaluate

$$\frac{21}{2}=10.5$$

Solution Steps

Calculate 2 to the power of -2 and get \frac{1}{4}.

$$\frac{1}{4}+27^{\frac{2}{3}}+5^{0}+\frac{1}{4}$$

Calculate 27 to the power of \frac{2}{3} and get 9.

$$\frac{1}{4}+9+5^{0}+\frac{1}{4}$$

Add \frac{1}{4} and 9 to get \frac{37}{4}.

$$\frac{37}{4}+5^{0}+\frac{1}{4}$$

Calculate 5 to the power of 0 and get 1.

$$\frac{37}{4}+1+\frac{1}{4}$$

Add \frac{37}{4} and 1 to get \frac{41}{4}.

$$\frac{41}{4}+\frac{1}{4}$$

Add \frac{41}{4} and \frac{1}{4} to get \frac{21}{2}.

$$\frac{21}{2}$$

Factor

$$\frac{3 \cdot 7}{2} = 10\frac{1}{2} = 10.5$$