Solve 13^2-x^2=left(29-xright)left(x+1right)

$${ 13 }^{ 2 } - { x }^{ 2 } = \left( 29-x \right) \left( x+1 \right)$$

Solve for x

$$x=5$$

Steps for Solving Linear Equation

Calculate 13 to the power of 2 and get 169.

$$169-x^{2}=\left(29-x\right)\left(x+1\right)$$

Use the distributive property to multiply 29-x by x+1 and combine like terms.

$$169-x^{2}=28x+29-x^{2}$$

Subtract 28x from both sides.

$$169-x^{2}-28x=29-x^{2}$$

Add x^{2} to both sides.

$$169-x^{2}-28x+x^{2}=29$$

Combine -x^{2} and x^{2} to get 0.

$$169-28x=29$$

Subtract 169 from both sides.

$$-28x=29-169$$

Subtract 169 from 29 to get -140.

$$-28x=-140$$

Divide both sides by -28.

$$x=\frac{-140}{-28}$$

Divide -140 by -28 to get 5.

$$x=5$$