Solve 12^3-11^410/15+10^5=

$${ 12 }^{ 3 } - { 11 }^{ 4 } \frac{ 10 }{ 15 } + { 10 }^{ 5 } =$$

Evaluate

$$\frac{275902}{3}\approx 91967.333333333$$

Solution Steps

Calculate 12 to the power of 3 and get 1728.

$$1728-11^{4}\times \frac{10}{15}+10^{5}$$

Calculate 11 to the power of 4 and get 14641.

$$1728-14641\times \frac{10}{15}+10^{5}$$

Reduce the fraction \frac{10}{15} to lowest terms by extracting and canceling out 5.

$$1728-14641\times \frac{2}{3}+10^{5}$$

Express 14641\times \frac{2}{3} as a single fraction.

$$1728-\frac{14641\times 2}{3}+10^{5}$$

Multiply 14641 and 2 to get 29282.

$$1728-\frac{29282}{3}+10^{5}$$

Convert 1728 to fraction \frac{5184}{3}.

$$\frac{5184}{3}-\frac{29282}{3}+10^{5}$$

Since \frac{5184}{3} and \frac{29282}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{5184-29282}{3}+10^{5}$$

Subtract 29282 from 5184 to get -24098.

$$-\frac{24098}{3}+10^{5}$$

Calculate 10 to the power of 5 and get 100000.

$$-\frac{24098}{3}+100000$$

Convert 100000 to fraction \frac{300000}{3}.

$$-\frac{24098}{3}+\frac{300000}{3}$$

Since -\frac{24098}{3} and \frac{300000}{3} have the same denominator, add them by adding their numerators.

$$\frac{-24098+300000}{3}$$

Add -24098 and 300000 to get 275902.

$$\frac{275902}{3}$$

Factor

$$\frac{2 \cdot 11 \cdot 12541}{3} = 91967\frac{1}{3} = 91967.33333333333$$