Solve 1^4+-2^4--2^3+0^7+{32}^0+8*{2}^2

$${ 1 }^{ 4 } + { -2 }^{ 4 } - { -2 }^{ 3 } + { 0 }^{ 7 } + { 32 }^{ 0 } +8 \times { 2 }^{ 2 }$$

Evaluate

$$58$$

Solution Steps

Calculate 1 to the power of 4 and get 1.

$$1+\left(-2\right)^{4}-\left(-2\right)^{3}+0^{7}+32^{0}+8\times 2^{2}$$

Calculate -2 to the power of 4 and get 16.

$$1+16-\left(-2\right)^{3}+0^{7}+32^{0}+8\times 2^{2}$$

Add 1 and 16 to get 17.

$$17-\left(-2\right)^{3}+0^{7}+32^{0}+8\times 2^{2}$$

Calculate -2 to the power of 3 and get -8.

$$17-\left(-8\right)+0^{7}+32^{0}+8\times 2^{2}$$

The opposite of -8 is 8.

$$17+8+0^{7}+32^{0}+8\times 2^{2}$$

Add 17 and 8 to get 25.

$$25+0^{7}+32^{0}+8\times 2^{2}$$

Calculate 0 to the power of 7 and get 0.

$$25+0+32^{0}+8\times 2^{2}$$

Add 25 and 0 to get 25.

$$25+32^{0}+8\times 2^{2}$$

Calculate 32 to the power of 0 and get 1.

$$25+1+8\times 2^{2}$$

Add 25 and 1 to get 26.

$$26+8\times 2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$26+8\times 4$$

Multiply 8 and 4 to get 32.

$$26+32$$

Add 26 and 32 to get 58.

$$58$$

Factor

$$2\times 29$$