Solve 1^2-4*(-1)*(-x)=0

$${ 1 }^{ 2 } -4 \times (-1) \times (-x)=0$$

Solve for x

$$x=\frac{1}{4}=0.25$$

Steps for Solving Linear Equation

Calculate 1 to the power of 2 and get 1.

$$1-4\left(-1\right)\left(-x\right)=0$$

Multiply 4 and -1 to get -4.

$$1-\left(-4\left(-x\right)\right)=0$$

Multiply -4 and -1 to get 4.

$$1-4x=0$$

Subtract 1 from both sides. Anything subtracted from zero gives its negation.

$$-4x=-1$$

Divide both sides by -4.

$$x=\frac{-1}{-4}$$

Fraction \frac{-1}{-4} can be simplified to \frac{1}{4} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{1}{4}$$