Solve left(z+2right)^2-5left(z+2right)

$${ \left(z+2 \right) }^{ 2 } -5 \left( z+2 \right)$$

Evaluate

$$\left(z-3\right)\left(z+2\right)$$

Solution Steps

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(z+2\right)^{2}.

$$z^{2}+4z+4-5\left(z+2\right)$$

Use the distributive property to multiply -5 by z+2.

$$z^{2}+4z+4-5z-10$$

Combine 4z and -5z to get -z.

$$z^{2}-z+4-10$$

Subtract 10 from 4 to get -6.

$$z^{2}-z-6$$

Expand

$$z^{2}-z-6$$

Solution Steps

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(z+2\right)^{2}.

$$z^{2}+4z+4-5\left(z+2\right)$$

Use the distributive property to multiply -5 by z+2.

$$z^{2}+4z+4-5z-10$$

Combine 4z and -5z to get -z.

$$z^{2}-z+4-10$$

Subtract 10 from 4 to get -6.

$$z^{2}-z-6$$