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x^{3}+9x^{2}+27x+27-x^{3}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+3\right)^{3}.
9x^{2}+27x+27
Combine x^{3} and -x^{3} to get 0.
x^{3}+9x^{2}+27x+27-x^{3}
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+3\right)^{3}.
9x^{2}+27x+27
Combine x^{3} and -x^{3} to get 0.