Solve left(3*2-3right)^2+left(4^2+2^2right)^2

$${ \left(3 \times 2-3 \right) }^{ 2 } + { \left( { 4 }^{ 2 } + { 2 }^{ 2 } \right) }^{ 2 }$$

Evaluate

$$409$$

Solution Steps

Multiply 3 and 2 to get 6.

$$\left(6-3\right)^{2}+\left(4^{2}+2^{2}\right)^{2}$$

Subtract 3 from 6 to get 3.

$$3^{2}+\left(4^{2}+2^{2}\right)^{2}$$

Calculate 3 to the power of 2 and get 9.

$$9+\left(4^{2}+2^{2}\right)^{2}$$

Calculate 4 to the power of 2 and get 16.

$$9+\left(16+2^{2}\right)^{2}$$

Calculate 2 to the power of 2 and get 4.

$$9+\left(16+4\right)^{2}$$

Add 16 and 4 to get 20.

$$9+20^{2}$$

Calculate 20 to the power of 2 and get 400.

$$9+400$$

Add 9 and 400 to get 409.

$$409$$

Factor

$$409$$