Solve left(14-xright)^2-x^2=56

$${ \left(14-x \right) }^{ 2 } - { x }^{ 2 } =56$$

Solve for x

$$x=5$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(14-x\right)^{2}.

$$196-28x+x^{2}-x^{2}=56$$

Combine x^{2} and -x^{2} to get 0.

$$196-28x=56$$

Subtract 196 from both sides.

$$-28x=56-196$$

Subtract 196 from 56 to get -140.

$$-28x=-140$$

Divide both sides by -28.

$$x=\frac{-140}{-28}$$

Divide -140 by -28 to get 5.

$$x=5$$