Solve left(1-xright)^296=54

$${ \left(1-x \right) }^{ 2 } 96=54$$

Solve for x

$$x=\frac{1}{4}=0.25$$

$$x = \frac{7}{4} = 1\frac{3}{4} = 1.75$$

Steps by Finding Square Root

Divide both sides by 96.

$$\frac{96\left(-x+1\right)^{2}}{96}=\frac{54}{96}$$

Dividing by 96 undoes the multiplication by 96.

$$\left(-x+1\right)^{2}=\frac{54}{96}$$

Reduce the fraction \frac{54}{96} to lowest terms by extracting and canceling out 6.

$$\left(-x+1\right)^{2}=\frac{9}{16}$$

Take the square root of both sides of the equation.

$$-x+1=\frac{3}{4} -x+1=-\frac{3}{4}$$

Subtract 1 from both sides of the equation.

$$-x+1-1=\frac{3}{4}-1 -x+1-1=-\frac{3}{4}-1$$

Subtracting 1 from itself leaves 0.

$$-x=\frac{3}{4}-1 -x=-\frac{3}{4}-1$$

Subtract 1 from \frac{3}{4}.

$$-x=-\frac{1}{4}$$

Subtract 1 from -\frac{3}{4}.

$$-x=-\frac{7}{4}$$

Divide both sides by -1.

$$\frac{-x}{-1}=-\frac{\frac{1}{4}}{-1} \frac{-x}{-1}=-\frac{\frac{7}{4}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=-\frac{\frac{1}{4}}{-1} x=-\frac{\frac{7}{4}}{-1}$$

Divide -\frac{1}{4} by -1.

$$x=\frac{1}{4}$$

Divide -\frac{7}{4} by -1.

$$x=\frac{7}{4}$$

The equation is now solved.

$$x=\frac{1}{4} x=\frac{7}{4}$$