Solve left(1-xright)^2=81/64

$${ \left(1-x \right) }^{ 2 } = \frac{ 81 }{ 64 }$$

Solve for x

$$x=-\frac{1}{8}=-0.125$$

$$x = \frac{17}{8} = 2\frac{1}{8} = 2.125$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$-x+1=\frac{9}{8} -x+1=-\frac{9}{8}$$

Subtract 1 from both sides of the equation.

$$-x+1-1=\frac{9}{8}-1 -x+1-1=-\frac{9}{8}-1$$

Subtracting 1 from itself leaves 0.

$$-x=\frac{9}{8}-1 -x=-\frac{9}{8}-1$$

Subtract 1 from \frac{9}{8}.

$$-x=\frac{1}{8}$$

Subtract 1 from -\frac{9}{8}.

$$-x=-\frac{17}{8}$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{\frac{1}{8}}{-1} \frac{-x}{-1}=-\frac{\frac{17}{8}}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{\frac{1}{8}}{-1} x=-\frac{\frac{17}{8}}{-1}$$

Divide \frac{1}{8} by -1.

$$x=-\frac{1}{8}$$

Divide -\frac{17}{8} by -1.

$$x=\frac{17}{8}$$

The equation is now solved.

$$x=-\frac{1}{8} x=\frac{17}{8}$$