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\left(-7\right)^{2}x^{2}-14-14=0
Expand \left(-7x\right)^{2}.
49x^{2}-14-14=0
Calculate -7 to the power of 2 and get 49.
49x^{2}-28=0
Subtract 14 from -14 to get -28.
49x^{2}=28
Add 28 to both sides. Anything plus zero gives itself.
x^{2}=\frac{28}{49}
Divide both sides by 49.
x^{2}=\frac{4}{7}
Reduce the fraction \frac{28}{49} to lowest terms by extracting and canceling out 7.
x=\frac{2\sqrt{7}}{7} x=-\frac{2\sqrt{7}}{7}
Take the square root of both sides of the equation.
\left(-7\right)^{2}x^{2}-14-14=0
Expand \left(-7x\right)^{2}.
49x^{2}-14-14=0
Calculate -7 to the power of 2 and get 49.
49x^{2}-28=0
Subtract 14 from -14 to get -28.
x=\frac{0±\sqrt{0^{2}-4\times 49\left(-28\right)}}{2\times 49}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 49 for a, 0 for b, and -28 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 49\left(-28\right)}}{2\times 49}
Square 0.
x=\frac{0±\sqrt{-196\left(-28\right)}}{2\times 49}
Multiply -4 times 49.
x=\frac{0±\sqrt{5488}}{2\times 49}
Multiply -196 times -28.
x=\frac{0±28\sqrt{7}}{2\times 49}
Take the square root of 5488.
x=\frac{0±28\sqrt{7}}{98}
Multiply 2 times 49.
x=\frac{2\sqrt{7}}{7}
Now solve the equation x=\frac{0±28\sqrt{7}}{98} when ± is plus.
x=-\frac{2\sqrt{7}}{7}
Now solve the equation x=\frac{0±28\sqrt{7}}{98} when ± is minus.
x=\frac{2\sqrt{7}}{7} x=-\frac{2\sqrt{7}}{7}
The equation is now solved.