Solve {left(-17sqrt{7}right)}^2-4*sqrt{7}*60sqrt{7}

$${ \left(-17 \sqrt{ 7 } \right) }^{ 2 } -4 \times \sqrt{ 7 } \times 60 \sqrt{ 7 }$$

Evaluate

$$343$$

Solution Steps

Multiply \sqrt{7} and \sqrt{7} to get 7.

$$\left(-17\sqrt{7}\right)^{2}-4\times 60\times 7$$

Expand \left(-17\sqrt{7}\right)^{2}.

$$\left(-17\right)^{2}\left(\sqrt{7}\right)^{2}-4\times 60\times 7$$

Calculate -17 to the power of 2 and get 289.

$$289\left(\sqrt{7}\right)^{2}-4\times 60\times 7$$

The square of \sqrt{7} is 7.

$$289\times 7-4\times 60\times 7$$

Multiply 289 and 7 to get 2023.

$$2023-4\times 60\times 7$$

Multiply 4 and 60 to get 240.

$$2023-240\times 7$$

Multiply 240 and 7 to get 1680.

$$2023-1680$$

Subtract 1680 from 2023 to get 343.

$$343$$

Factor

$$7^{3}$$