Solve left((-1)right)^2-x+y=-5

$${ \left((-1) \right) }^{ 2 } -x+y=-5$$

Solve for x

$$x=y+6$$

Steps for Solving Linear Equation

Calculate -1 to the power of 2 and get 1.

$$1-x+y=-5$$

Subtract 1 from both sides.

$$-x+y=-5-1$$

Subtract 1 from -5 to get -6.

$$-x+y=-6$$

Subtract y from both sides.

$$-x=-6-y$$

The equation is in standard form.

$$-x=-y-6$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{-y-6}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{-y-6}{-1}$$

Divide -6-y by -1.

$$x=y+6$$

Solve for y

$$y=x-6$$

Solution Steps

Calculate -1 to the power of 2 and get 1.

$$1-x+y=-5$$

Subtract 1 from both sides.

$$-x+y=-5-1$$

Subtract 1 from -5 to get -6.

$$-x+y=-6$$

Add x to both sides.

$$y=-6+x$$