Solve left(-2^-2right)^3-2^3*(-2^1)

$${ \left( { -2 }^{ -2 } \right) }^{ 3 } { -2 }^{ 3 } \times ( { -2 }^{ 1 } )$$

Evaluate

$$\frac{1}{4}=0.25$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply -2 and 3 to get -6.

$$\left(-2\right)^{-6}\left(-2\right)^{3}\left(-2\right)^{1}$$

To multiply powers of the same base, add their exponents. Add -6 and 3 to get -3.

$$\left(-2\right)^{-3}\left(-2\right)^{1}$$

To multiply powers of the same base, add their exponents. Add -3 and 1 to get -2.

$$\left(-2\right)^{-2}$$

Calculate -2 to the power of -2 and get \frac{1}{4}.

$$\frac{1}{4}$$

Factor

$$\frac{1}{2 ^ {2}} = 0.25$$