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12-2\sqrt{35}\approx 0.167840434
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12-2\sqrt{35}
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\left(\sqrt{7}\right)^{2}-2\sqrt{7}\sqrt{5}+\left(\sqrt{5}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{7}-\sqrt{5}\right)^{2}.
7-2\sqrt{7}\sqrt{5}+\left(\sqrt{5}\right)^{2}
The square of \sqrt{7} is 7.
7-2\sqrt{35}+\left(\sqrt{5}\right)^{2}
To multiply \sqrt{7} and \sqrt{5}, multiply the numbers under the square root.
7-2\sqrt{35}+5
The square of \sqrt{5} is 5.
12-2\sqrt{35}
Add 7 and 5 to get 12.
\left(\sqrt{7}\right)^{2}-2\sqrt{7}\sqrt{5}+\left(\sqrt{5}\right)^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\sqrt{7}-\sqrt{5}\right)^{2}.
7-2\sqrt{7}\sqrt{5}+\left(\sqrt{5}\right)^{2}
The square of \sqrt{7} is 7.
7-2\sqrt{35}+\left(\sqrt{5}\right)^{2}
To multiply \sqrt{7} and \sqrt{5}, multiply the numbers under the square root.
7-2\sqrt{35}+5
The square of \sqrt{5} is 5.
12-2\sqrt{35}
Add 7 and 5 to get 12.
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