Evaluate
82
Factor
2\times 41
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\left(\sqrt{46}\right)^{2}+12\sqrt{46}+36-12\sqrt{46}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(\sqrt{46}+6\right)^{2}.
46+12\sqrt{46}+36-12\sqrt{46}
The square of \sqrt{46} is 46.
82+12\sqrt{46}-12\sqrt{46}
Add 46 and 36 to get 82.
82
Combine 12\sqrt{46} and -12\sqrt{46} to get 0.
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