Solve {left(14/3right)}^2+4/9-64/9

$${ \left( \frac{ 14 }{ 3 } \right) }^{ 2 } + \frac{ 4 }{ 9 } - \frac{ 64 }{ 9 }$$

Evaluate

$$\frac{136}{9}\approx 15.111111111$$

Solution Steps

Calculate \frac{14}{3} to the power of 2 and get \frac{196}{9}.

$$\frac{196}{9}+\frac{4}{9}-\frac{64}{9}$$

Since \frac{196}{9} and \frac{4}{9} have the same denominator, add them by adding their numerators.

$$\frac{196+4}{9}-\frac{64}{9}$$

Add 196 and 4 to get 200.

$$\frac{200}{9}-\frac{64}{9}$$

Since \frac{200}{9} and \frac{64}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{200-64}{9}$$

Subtract 64 from 200 to get 136.

$$\frac{136}{9}$$

Factor

$$\frac{2 ^ {3} \cdot 17}{3 ^ {2}} = 15\frac{1}{9} = 15.11111111111111$$