Solve {left(1/9right)}^2*36+2*18/5

$${ \left( \frac{ 1 }{ 9 } \right) }^{ 2 } \times 36+2 \times \frac{ 18 }{ 5 }$$

Evaluate

$$\frac{344}{45}\approx 7.644444444$$

Solution Steps

Calculate \frac{1}{9} to the power of 2 and get \frac{1}{81}.

$$\frac{1}{81}\times 36+2\times \frac{18}{5}$$

Multiply \frac{1}{81} and 36 to get \frac{36}{81}.

$$\frac{36}{81}+2\times \frac{18}{5}$$

Reduce the fraction \frac{36}{81} to lowest terms by extracting and canceling out 9.

$$\frac{4}{9}+2\times \frac{18}{5}$$

Express 2\times \frac{18}{5} as a single fraction.

$$\frac{4}{9}+\frac{2\times 18}{5}$$

Multiply 2 and 18 to get 36.

$$\frac{4}{9}+\frac{36}{5}$$

Least common multiple of 9 and 5 is 45. Convert \frac{4}{9} and \frac{36}{5} to fractions with denominator 45.

$$\frac{20}{45}+\frac{324}{45}$$

Since \frac{20}{45} and \frac{324}{45} have the same denominator, add them by adding their numerators.

$$\frac{20+324}{45}$$

Add 20 and 324 to get 344.

$$\frac{344}{45}$$

Factor

$$\frac{2 ^ {3} \cdot 43}{3 ^ {2} \cdot 5} = 7\frac{29}{45} = 7.644444444444445$$