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\frac{1}{9}x^{2}-2xy+9y^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\frac{1}{3}x-3y\right)^{2}.
\frac{1}{9}x^{2}-2xy+9y^{2}
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(\frac{1}{3}x-3y\right)^{2}.