Solve {left(1/2right)}^2-2*1/2-8

$${ \left( \frac{ 1 }{ 2 } \right) }^{ 2 } -2 \times \frac{ 1 }{ 2 } -8$$

Evaluate

$$-\frac{35}{4}=-8.75$$

Solution Steps

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{1}{4}-2\times \frac{1}{2}-8$$

Cancel out 2 and 2.

$$\frac{1}{4}-1-8$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{1}{4}-\frac{4}{4}-8$$

Since \frac{1}{4} and \frac{4}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-4}{4}-8$$

Subtract 4 from 1 to get -3.

$$-\frac{3}{4}-8$$

Convert 8 to fraction \frac{32}{4}.

$$-\frac{3}{4}-\frac{32}{4}$$

Since -\frac{3}{4} and \frac{32}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-32}{4}$$

Subtract 32 from -3 to get -35.

$$-\frac{35}{4}$$

Factor

$$-\frac{35}{4} = -8\frac{3}{4} = -8.75$$