Solve for f (complex solution)
\left\{\begin{matrix}f=\frac{2\pi \epsilon z^{x}}{x}\text{, }&x\neq 0\\f\in \mathrm{C}\text{, }&\epsilon =0\text{ and }x=0\end{matrix}\right.
Solve for f
\left\{\begin{matrix}f=\frac{2\pi \epsilon z^{x}}{x}\text{, }&\left(x\neq 0\text{ and }z>0\right)\text{ or }\left(z=0\text{ and }x>0\right)\text{ or }\left(x\neq 0\text{ and }z<0\text{ and }Denominator(x)\text{bmod}2=1\right)\\f\in \mathrm{R}\text{, }&x=0\text{ and }\epsilon =0\text{ and }z\neq 0\end{matrix}\right.
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\varepsilon \cdot z ^ {x} 2 * \pi = {(x)} f
Substitute 2 * \pi for \tau.
xf=\epsilon z^{x}\times 2\pi
Swap sides so that all variable terms are on the left hand side.
xf=2\pi \epsilon z^{x}
The equation is in standard form.
\frac{xf}{x}=\frac{2\pi \epsilon z^{x}}{x}
Divide both sides by x.
f=\frac{2\pi \epsilon z^{x}}{x}
Dividing by x undoes the multiplication by x.
\varepsilon \cdot z ^ {x} 2 * \pi = {(x)} f
Substitute 2 * \pi for \tau.
xf=\epsilon z^{x}\times 2\pi
Swap sides so that all variable terms are on the left hand side.
xf=2\pi \epsilon z^{x}
The equation is in standard form.
\frac{xf}{x}=\frac{2\pi \epsilon z^{x}}{x}
Divide both sides by x.
f=\frac{2\pi \epsilon z^{x}}{x}
Dividing by x undoes the multiplication by x.
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