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2\sqrt{2}-\sqrt{2}\sqrt{2+2}
Factor 8=2^{2}\times 2. Rewrite the square root of the product \sqrt{2^{2}\times 2} as the product of square roots \sqrt{2^{2}}\sqrt{2}. Take the square root of 2^{2}.
2\sqrt{2}-\sqrt{2}\sqrt{4}
Add 2 and 2 to get 4.
2\sqrt{2}-\sqrt{2}\times 2
Calculate the square root of 4 and get 2.
0
Combine 2\sqrt{2} and -\sqrt{2}\times 2 to get 0.
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