Solve sqrt{6left(1+1/2^2+1/3^2+1/4^2+1/5^2+frac{1}{{6}^{2}}+frac{1}{{7}^{2}}+frac{1}{{8}^{2}}+frac{1}{{9}^{2}}+frac{1}{{10}^{2}}+frac{1}{{11}^{2}}+frac{1}{{12}^{2}}+frac{1}{{13}^{2}}+frac{1}{{14}^{2}}+frac{1}{{15}^{2}}+frac{1}{{16}^{2}}+frac{1}{{17}^{2}}+frac{1}{{18}^{2}}+frac{1}{{19}^2}+frac{1}{{20}^2}+frac{1}{{21}^2}+frac{1}{{22}^2}right)}

$$\sqrt{ 6 \left( 1+ \frac{ 1 }{ { 2 }^{ 2 } } + \frac{ 1 }{ { 3 }^{ 2 } } + \frac{ 1 }{ { 4 }^{ 2 } } + \frac{ 1 }{ { 5 }^{ 2 } } + \frac{ 1 }{ { 6 }^{ 2 } } + \frac{ 1 }{ { 7 }^{ 2 } } + \frac{ 1 }{ { 8 }^{ 2 } } + \frac{ 1 }{ { 9 }^{ 2 } } + \frac{ 1 }{ { 10 }^{ 2 } } + \frac{ 1 }{ { 11 }^{ 2 } } + \frac{ 1 }{ { 12 }^{ 2 } } + \frac{ 1 }{ { 13 }^{ 2 } } + \frac{ 1 }{ { 14 }^{ 2 } } + \frac{ 1 }{ { 15 }^{ 2 } } + \frac{ 1 }{ { 16 }^{ 2 } } + \frac{ 1 }{ { 17 }^{ 2 } } + \frac{ 1 }{ { 18 }^{ 2 } } + \frac{ 1 }{ { 19 }^{ 2 } } + \frac{ 1 }{ { 20 }^{ 2 } } + \frac{ 1 }{ { 21 }^{ 2 } } + \frac{ 1 }{ { 22 }^{ 2 } } \right) }$$

Evaluate

$$\frac{\sqrt{10620579377514270}}{33256080}\approx 3.098867793$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\sqrt{6\left(1+\frac{1}{4}+\frac{1}{3^{2}}+\frac{1}{4^{2}}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Convert 1 to fraction \frac{4}{4}.

$$\sqrt{6\left(\frac{4}{4}+\frac{1}{4}+\frac{1}{3^{2}}+\frac{1}{4^{2}}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{4}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{4+1}{4}+\frac{1}{3^{2}}+\frac{1}{4^{2}}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 4 and 1 to get 5.

$$\sqrt{6\left(\frac{5}{4}+\frac{1}{3^{2}}+\frac{1}{4^{2}}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 3 to the power of 2 and get 9.

$$\sqrt{6\left(\frac{5}{4}+\frac{1}{9}+\frac{1}{4^{2}}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 4 and 9 is 36. Convert \frac{5}{4} and \frac{1}{9} to fractions with denominator 36.

$$\sqrt{6\left(\frac{45}{36}+\frac{4}{36}+\frac{1}{4^{2}}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{45}{36} and \frac{4}{36} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{45+4}{36}+\frac{1}{4^{2}}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 45 and 4 to get 49.

$$\sqrt{6\left(\frac{49}{36}+\frac{1}{4^{2}}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 4 to the power of 2 and get 16.

$$\sqrt{6\left(\frac{49}{36}+\frac{1}{16}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 36 and 16 is 144. Convert \frac{49}{36} and \frac{1}{16} to fractions with denominator 144.

$$\sqrt{6\left(\frac{196}{144}+\frac{9}{144}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{196}{144} and \frac{9}{144} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{196+9}{144}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 196 and 9 to get 205.

$$\sqrt{6\left(\frac{205}{144}+\frac{1}{5^{2}}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 5 to the power of 2 and get 25.

$$\sqrt{6\left(\frac{205}{144}+\frac{1}{25}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 144 and 25 is 3600. Convert \frac{205}{144} and \frac{1}{25} to fractions with denominator 3600.

$$\sqrt{6\left(\frac{5125}{3600}+\frac{144}{3600}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{5125}{3600} and \frac{144}{3600} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{5125+144}{3600}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 5125 and 144 to get 5269.

$$\sqrt{6\left(\frac{5269}{3600}+\frac{1}{6^{2}}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 6 to the power of 2 and get 36.

$$\sqrt{6\left(\frac{5269}{3600}+\frac{1}{36}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 3600 and 36 is 3600. Convert \frac{5269}{3600} and \frac{1}{36} to fractions with denominator 3600.

$$\sqrt{6\left(\frac{5269}{3600}+\frac{100}{3600}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{5269}{3600} and \frac{100}{3600} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{5269+100}{3600}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 5269 and 100 to get 5369.

$$\sqrt{6\left(\frac{5369}{3600}+\frac{1}{7^{2}}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 7 to the power of 2 and get 49.

$$\sqrt{6\left(\frac{5369}{3600}+\frac{1}{49}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 3600 and 49 is 176400. Convert \frac{5369}{3600} and \frac{1}{49} to fractions with denominator 176400.

$$\sqrt{6\left(\frac{263081}{176400}+\frac{3600}{176400}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{263081}{176400} and \frac{3600}{176400} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{263081+3600}{176400}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 263081 and 3600 to get 266681.

$$\sqrt{6\left(\frac{266681}{176400}+\frac{1}{8^{2}}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 8 to the power of 2 and get 64.

$$\sqrt{6\left(\frac{266681}{176400}+\frac{1}{64}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 176400 and 64 is 705600. Convert \frac{266681}{176400} and \frac{1}{64} to fractions with denominator 705600.

$$\sqrt{6\left(\frac{1066724}{705600}+\frac{11025}{705600}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{1066724}{705600} and \frac{11025}{705600} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{1066724+11025}{705600}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 1066724 and 11025 to get 1077749.

$$\sqrt{6\left(\frac{1077749}{705600}+\frac{1}{9^{2}}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 9 to the power of 2 and get 81.

$$\sqrt{6\left(\frac{1077749}{705600}+\frac{1}{81}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 705600 and 81 is 6350400. Convert \frac{1077749}{705600} and \frac{1}{81} to fractions with denominator 6350400.

$$\sqrt{6\left(\frac{9699741}{6350400}+\frac{78400}{6350400}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{9699741}{6350400} and \frac{78400}{6350400} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{9699741+78400}{6350400}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 9699741 and 78400 to get 9778141.

$$\sqrt{6\left(\frac{9778141}{6350400}+\frac{1}{10^{2}}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 10 to the power of 2 and get 100.

$$\sqrt{6\left(\frac{9778141}{6350400}+\frac{1}{100}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 6350400 and 100 is 6350400. Convert \frac{9778141}{6350400} and \frac{1}{100} to fractions with denominator 6350400.

$$\sqrt{6\left(\frac{9778141}{6350400}+\frac{63504}{6350400}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{9778141}{6350400} and \frac{63504}{6350400} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{9778141+63504}{6350400}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 9778141 and 63504 to get 9841645.

$$\sqrt{6\left(\frac{9841645}{6350400}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Reduce the fraction \frac{9841645}{6350400} to lowest terms by extracting and canceling out 5.

$$\sqrt{6\left(\frac{1968329}{1270080}+\frac{1}{11^{2}}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 11 to the power of 2 and get 121.

$$\sqrt{6\left(\frac{1968329}{1270080}+\frac{1}{121}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 1270080 and 121 is 153679680. Convert \frac{1968329}{1270080} and \frac{1}{121} to fractions with denominator 153679680.

$$\sqrt{6\left(\frac{238167809}{153679680}+\frac{1270080}{153679680}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{238167809}{153679680} and \frac{1270080}{153679680} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{238167809+1270080}{153679680}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 238167809 and 1270080 to get 239437889.

$$\sqrt{6\left(\frac{239437889}{153679680}+\frac{1}{12^{2}}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 12 to the power of 2 and get 144.

$$\sqrt{6\left(\frac{239437889}{153679680}+\frac{1}{144}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 153679680 and 144 is 153679680. Convert \frac{239437889}{153679680} and \frac{1}{144} to fractions with denominator 153679680.

$$\sqrt{6\left(\frac{239437889}{153679680}+\frac{1067220}{153679680}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{239437889}{153679680} and \frac{1067220}{153679680} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{239437889+1067220}{153679680}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 239437889 and 1067220 to get 240505109.

$$\sqrt{6\left(\frac{240505109}{153679680}+\frac{1}{13^{2}}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 13 to the power of 2 and get 169.

$$\sqrt{6\left(\frac{240505109}{153679680}+\frac{1}{169}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 153679680 and 169 is 25971865920. Convert \frac{240505109}{153679680} and \frac{1}{169} to fractions with denominator 25971865920.

$$\sqrt{6\left(\frac{40645363421}{25971865920}+\frac{153679680}{25971865920}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{40645363421}{25971865920} and \frac{153679680}{25971865920} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{40645363421+153679680}{25971865920}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 40645363421 and 153679680 to get 40799043101.

$$\sqrt{6\left(\frac{40799043101}{25971865920}+\frac{1}{14^{2}}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 14 to the power of 2 and get 196.

$$\sqrt{6\left(\frac{40799043101}{25971865920}+\frac{1}{196}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 25971865920 and 196 is 25971865920. Convert \frac{40799043101}{25971865920} and \frac{1}{196} to fractions with denominator 25971865920.

$$\sqrt{6\left(\frac{40799043101}{25971865920}+\frac{132509520}{25971865920}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{40799043101}{25971865920} and \frac{132509520}{25971865920} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{40799043101+132509520}{25971865920}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 40799043101 and 132509520 to get 40931552621.

$$\sqrt{6\left(\frac{40931552621}{25971865920}+\frac{1}{15^{2}}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 15 to the power of 2 and get 225.

$$\sqrt{6\left(\frac{40931552621}{25971865920}+\frac{1}{225}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 25971865920 and 225 is 129859329600. Convert \frac{40931552621}{25971865920} and \frac{1}{225} to fractions with denominator 129859329600.

$$\sqrt{6\left(\frac{204657763105}{129859329600}+\frac{577152576}{129859329600}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{204657763105}{129859329600} and \frac{577152576}{129859329600} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{204657763105+577152576}{129859329600}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 204657763105 and 577152576 to get 205234915681.

$$\sqrt{6\left(\frac{205234915681}{129859329600}+\frac{1}{16^{2}}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 16 to the power of 2 and get 256.

$$\sqrt{6\left(\frac{205234915681}{129859329600}+\frac{1}{256}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 129859329600 and 256 is 519437318400. Convert \frac{205234915681}{129859329600} and \frac{1}{256} to fractions with denominator 519437318400.

$$\sqrt{6\left(\frac{820939662724}{519437318400}+\frac{2029052025}{519437318400}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{820939662724}{519437318400} and \frac{2029052025}{519437318400} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{820939662724+2029052025}{519437318400}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 820939662724 and 2029052025 to get 822968714749.

$$\sqrt{6\left(\frac{822968714749}{519437318400}+\frac{1}{17^{2}}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 17 to the power of 2 and get 289.

$$\sqrt{6\left(\frac{822968714749}{519437318400}+\frac{1}{289}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 519437318400 and 289 is 150117385017600. Convert \frac{822968714749}{519437318400} and \frac{1}{289} to fractions with denominator 150117385017600.

$$\sqrt{6\left(\frac{237837958562461}{150117385017600}+\frac{519437318400}{150117385017600}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{237837958562461}{150117385017600} and \frac{519437318400}{150117385017600} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{237837958562461+519437318400}{150117385017600}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 237837958562461 and 519437318400 to get 238357395880861.

$$\sqrt{6\left(\frac{238357395880861}{150117385017600}+\frac{1}{18^{2}}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 18 to the power of 2 and get 324.

$$\sqrt{6\left(\frac{238357395880861}{150117385017600}+\frac{1}{324}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 150117385017600 and 324 is 150117385017600. Convert \frac{238357395880861}{150117385017600} and \frac{1}{324} to fractions with denominator 150117385017600.

$$\sqrt{6\left(\frac{238357395880861}{150117385017600}+\frac{463325262400}{150117385017600}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{238357395880861}{150117385017600} and \frac{463325262400}{150117385017600} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{238357395880861+463325262400}{150117385017600}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 238357395880861 and 463325262400 to get 238820721143261.

$$\sqrt{6\left(\frac{238820721143261}{150117385017600}+\frac{1}{19^{2}}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 19 to the power of 2 and get 361.

$$\sqrt{6\left(\frac{238820721143261}{150117385017600}+\frac{1}{361}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 150117385017600 and 361 is 54192375991353600. Convert \frac{238820721143261}{150117385017600} and \frac{1}{361} to fractions with denominator 54192375991353600.

$$\sqrt{6\left(\frac{86214280332717221}{54192375991353600}+\frac{150117385017600}{54192375991353600}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{86214280332717221}{54192375991353600} and \frac{150117385017600}{54192375991353600} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{86214280332717221+150117385017600}{54192375991353600}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 86214280332717221 and 150117385017600 to get 86364397717734821.

$$\sqrt{6\left(\frac{86364397717734821}{54192375991353600}+\frac{1}{20^{2}}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 20 to the power of 2 and get 400.

$$\sqrt{6\left(\frac{86364397717734821}{54192375991353600}+\frac{1}{400}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 54192375991353600 and 400 is 54192375991353600. Convert \frac{86364397717734821}{54192375991353600} and \frac{1}{400} to fractions with denominator 54192375991353600.

$$\sqrt{6\left(\frac{86364397717734821}{54192375991353600}+\frac{135480939978384}{54192375991353600}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Since \frac{86364397717734821}{54192375991353600} and \frac{135480939978384}{54192375991353600} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{86364397717734821+135480939978384}{54192375991353600}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Add 86364397717734821 and 135480939978384 to get 86499878657713205.

$$\sqrt{6\left(\frac{86499878657713205}{54192375991353600}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Reduce the fraction \frac{86499878657713205}{54192375991353600} to lowest terms by extracting and canceling out 5.

$$\sqrt{6\left(\frac{17299975731542641}{10838475198270720}+\frac{1}{21^{2}}+\frac{1}{22^{2}}\right)}$$

Calculate 21 to the power of 2 and get 441.

$$\sqrt{6\left(\frac{17299975731542641}{10838475198270720}+\frac{1}{441}+\frac{1}{22^{2}}\right)}$$

Least common multiple of 10838475198270720 and 441 is 10838475198270720. Convert \frac{17299975731542641}{10838475198270720} and \frac{1}{441} to fractions with denominator 10838475198270720.

$$\sqrt{6\left(\frac{17299975731542641}{10838475198270720}+\frac{24577041265920}{10838475198270720}+\frac{1}{22^{2}}\right)}$$

Since \frac{17299975731542641}{10838475198270720} and \frac{24577041265920}{10838475198270720} have the same denominator, add them by adding their numerators.

$$\sqrt{6\left(\frac{17299975731542641+24577041265920}{10838475198270720}+\frac{1}{22^{2}}\right)}$$

Add 17299975731542641 and 24577041265920 to get 17324552772808561.

$$\sqrt{6\left(\frac{17324552772808561}{10838475198270720}+\frac{1}{22^{2}}\right)}$$

Reduce the fraction \frac{17324552772808561}{10838475198270720} to lowest terms by extracting and canceling out 49.

$$\sqrt{6\left(\frac{353562301485889}{221193371393280}+\frac{1}{22^{2}}\right)}$$

Calculate 22 to the power of 2 and get 484.

$$\sqrt{6\left(\frac{353562301485889}{221193371393280}+\frac{1}{484}\right)}$$

Least common multiple of 221193371393280 and 484 is 221193371393280. Convert \frac{353562301485889}{221193371393280} and \frac{1}{484} to fractions with denominator 221193371393280.

$$\sqrt{6\left(\frac{353562301485889}{221193371393280}+\frac{457011097920}{221193371393280}\right)}$$

Since \frac{353562301485889}{221193371393280} and \frac{457011097920}{221193371393280} have the same denominator, add them by adding their numerators.

$$\sqrt{6\times \frac{353562301485889+457011097920}{221193371393280}}$$

Add 353562301485889 and 457011097920 to get 354019312583809.

$$\sqrt{6\times \frac{354019312583809}{221193371393280}}$$

Express 6\times \frac{354019312583809}{221193371393280} as a single fraction.

$$\sqrt{\frac{6\times 354019312583809}{221193371393280}}$$

Multiply 6 and 354019312583809 to get 2124115875502854.

$$\sqrt{\frac{2124115875502854}{221193371393280}}$$

Reduce the fraction \frac{2124115875502854}{221193371393280} to lowest terms by extracting and canceling out 6.

$$\sqrt{\frac{354019312583809}{36865561898880}}$$

Rewrite the square root of the division \sqrt{\frac{354019312583809}{36865561898880}} as the division of square roots \frac{\sqrt{354019312583809}}{\sqrt{36865561898880}}.

$$\frac{\sqrt{354019312583809}}{\sqrt{36865561898880}}$$

Factor 36865561898880=1108536^{2}\times 30. Rewrite the square root of the product \sqrt{1108536^{2}\times 30} as the product of square roots \sqrt{1108536^{2}}\sqrt{30}. Take the square root of 1108536^{2}.

$$\frac{\sqrt{354019312583809}}{1108536\sqrt{30}}$$

Rationalize the denominator of \frac{\sqrt{354019312583809}}{1108536\sqrt{30}} by multiplying numerator and denominator by \sqrt{30}.

$$\frac{\sqrt{354019312583809}\sqrt{30}}{1108536\left(\sqrt{30}\right)^{2}}$$

The square of \sqrt{30} is 30.

$$\frac{\sqrt{354019312583809}\sqrt{30}}{1108536\times 30}$$

To multiply \sqrt{354019312583809} and \sqrt{30}, multiply the numbers under the square root.

$$\frac{\sqrt{10620579377514270}}{1108536\times 30}$$

Multiply 1108536 and 30 to get 33256080.

$$\frac{\sqrt{10620579377514270}}{33256080}$$