Solve for x
x=3
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\left(\sqrt{4x+1}\right)^{2}=\left(\sqrt{x+10}\right)^{2}
Square both sides of the equation.
4x+1=\left(\sqrt{x+10}\right)^{2}
Calculate \sqrt{4x+1} to the power of 2 and get 4x+1.
4x+1=x+10
Calculate \sqrt{x+10} to the power of 2 and get x+10.
4x+1-x=10
Subtract x from both sides.
3x+1=10
Combine 4x and -x to get 3x.
3x=10-1
Subtract 1 from both sides.
3x=9
Subtract 1 from 10 to get 9.
x=\frac{9}{3}
Divide both sides by 3.
x=3
Divide 9 by 3 to get 3.
\sqrt{4\times 3+1}=\sqrt{3+10}
Substitute 3 for x in the equation \sqrt{4x+1}=\sqrt{x+10}.
13^{\frac{1}{2}}=13^{\frac{1}{2}}
Simplify. The value x=3 satisfies the equation.
x=3
Equation \sqrt{4x+1}=\sqrt{x+10} has a unique solution.
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