Solve for x
x=\frac{z^{2}}{3}
z\leq 0
Solve for z
z=-\sqrt{3x}
x\geq 0
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\sqrt{3x}+z-z=-z
Subtract z from both sides of the equation.
\sqrt{3x}=-z
Subtracting z from itself leaves 0.
3x=z^{2}
Square both sides of the equation.
\frac{3x}{3}=\frac{z^{2}}{3}
Divide both sides by 3.
x=\frac{z^{2}}{3}
Dividing by 3 undoes the multiplication by 3.
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