Solve sqrt{27}+sqrt{48}

$$\sqrt{ 27 } + \sqrt{ 48 }$$

Evaluate

$$7\sqrt{3}\approx 12.124355653$$

Solution Steps

Factor 27=3^{2}\times 3. Rewrite the square root of the product \sqrt{3^{2}\times 3} as the product of square roots \sqrt{3^{2}}\sqrt{3}. Take the square root of 3^{2}.

$$3\sqrt{3}+\sqrt{48}$$

Factor 48=4^{2}\times 3. Rewrite the square root of the product \sqrt{4^{2}\times 3} as the product of square roots \sqrt{4^{2}}\sqrt{3}. Take the square root of 4^{2}.

$$3\sqrt{3}+4\sqrt{3}$$

Combine 3\sqrt{3} and 4\sqrt{3} to get 7\sqrt{3}.

$$7\sqrt{3}$$