Solve for x
x=\sqrt{2}+\sqrt{3}\approx 3.14626437
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\sqrt{2}x=\sqrt{6}+2
The equation is in standard form.
\frac{\sqrt{2}x}{\sqrt{2}}=\frac{\sqrt{6}+2}{\sqrt{2}}
Divide both sides by \sqrt{2}.
x=\frac{\sqrt{6}+2}{\sqrt{2}}
Dividing by \sqrt{2} undoes the multiplication by \sqrt{2}.
x=\sqrt{2}+\sqrt{3}
Divide 2+\sqrt{6} by \sqrt{2}.
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