Solve sqrt{12-x}-5=0

$$\sqrt{ 12-x } -5=0$$

Solve for x

$$x=-13$$

Steps for Solving Radical Equations

Add 5 to both sides of the equation.

$$\sqrt{-x+12}-5-\left(-5\right)=-\left(-5\right)$$

Subtracting -5 from itself leaves 0.

$$\sqrt{-x+12}=-\left(-5\right)$$

Subtract -5 from 0.

$$\sqrt{-x+12}=5$$

Square both sides of the equation.

$$-x+12=25$$

Subtract 12 from both sides of the equation.

$$-x+12-12=25-12$$

Subtracting 12 from itself leaves 0.

$$-x=25-12$$

Subtract 12 from 25.

$$-x=13$$

Divide both sides by -1.

$$\frac{-x}{-1}=\frac{13}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$x=\frac{13}{-1}$$

Divide 13 by -1.

$$x=-13$$