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\sqrt{\frac{121}{9}+\left(\frac{11}{3}\right)^{2}}
Calculate \frac{11}{3} to the power of 2 and get \frac{121}{9}.
\sqrt{\frac{121}{9}+\frac{121}{9}}
Calculate \frac{11}{3} to the power of 2 and get \frac{121}{9}.
\sqrt{\frac{121+121}{9}}
Since \frac{121}{9} and \frac{121}{9} have the same denominator, add them by adding their numerators.
\sqrt{\frac{242}{9}}
Add 121 and 121 to get 242.
\frac{\sqrt{242}}{\sqrt{9}}
Rewrite the square root of the division \sqrt{\frac{242}{9}} as the division of square roots \frac{\sqrt{242}}{\sqrt{9}}.
\frac{11\sqrt{2}}{\sqrt{9}}
Factor 242=11^{2}\times 2. Rewrite the square root of the product \sqrt{11^{2}\times 2} as the product of square roots \sqrt{11^{2}}\sqrt{2}. Take the square root of 11^{2}.
\frac{11\sqrt{2}}{3}
Calculate the square root of 9 and get 3.