Solve sqrt{4^2+2(4)}

$$\sqrt{ { 4 }^{ 2 } +2(4) }$$

Evaluate

$$2\sqrt{6}\approx 4.898979486$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$\sqrt{16+2\times 4}$$

Multiply 2 and 4 to get 8.

$$\sqrt{16+8}$$

Add 16 and 8 to get 24.

$$\sqrt{24}$$

Factor 24=2^{2}\times 6. Rewrite the square root of the product \sqrt{2^{2}\times 6} as the product of square roots \sqrt{2^{2}}\sqrt{6}. Take the square root of 2^{2}.

$$2\sqrt{6}$$