Solve sqrt{2^2+1^2-2*2*1*(-025}

$$\sqrt{ { 2 }^{ 2 } + { 1 }^{ 2 } -2 \cdot 2 \cdot 1 \times (-025 }$$

Evaluate

$$\sqrt{105}\approx 10.246950766$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\sqrt{4+1^{2}-2\times 2\times 1\left(-25\right)}$$

Calculate 1 to the power of 2 and get 1.

$$\sqrt{4+1-2\times 2\times 1\left(-25\right)}$$

Add 4 and 1 to get 5.

$$\sqrt{5-2\times 2\times 1\left(-25\right)}$$

Multiply 2 and 2 to get 4.

$$\sqrt{5-4\times 1\left(-25\right)}$$

Multiply 4 and 1 to get 4.

$$\sqrt{5-4\left(-25\right)}$$

Multiply 4 and -25 to get -100.

$$\sqrt{5-\left(-100\right)}$$

The opposite of -100 is 100.

$$\sqrt{5+100}$$

Add 5 and 100 to get 105.

$$\sqrt{105}$$