Solve sqrt{left(3-(-4)right)^2}+left(2-3right)^2

$$\sqrt{ { \left(3-(-4) \right) }^{ 2 } } + { \left(2-3 \right) }^{ 2 }$$

Evaluate

$$8$$

Solution Steps

The opposite of -4 is 4.

$$\sqrt{\left(3+4\right)^{2}}+\left(2-3\right)^{2}$$

Add 3 and 4 to get 7.

$$\sqrt{7^{2}}+\left(2-3\right)^{2}$$

Calculate 7 to the power of 2 and get 49.

$$\sqrt{49}+\left(2-3\right)^{2}$$

Calculate the square root of 49 and get 7.

$$7+\left(2-3\right)^{2}$$

Subtract 3 from 2 to get -1.

$$7+\left(-1\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$7+1$$

Add 7 and 1 to get 8.

$$8$$

Factor

$$2^{3}$$