Solve sqrt{{left(3/4right)}^2}+1^2

$$\sqrt{ { \left( \frac{ 3 }{ 4 } \right) }^{ 2 } } + { 1 }^{ 2 }$$

Evaluate

$$\frac{7}{4}=1.75$$

Solution Steps

Calculate \frac{3}{4} to the power of 2 and get \frac{9}{16}.

$$\sqrt{\frac{9}{16}}+1^{2}$$

Rewrite the square root of the division \frac{9}{16} as the division of square roots \frac{\sqrt{9}}{\sqrt{16}}. Take the square root of both numerator and denominator.

$$\frac{3}{4}+1^{2}$$

Calculate 1 to the power of 2 and get 1.

$$\frac{3}{4}+1$$

Convert 1 to fraction \frac{4}{4}.

$$\frac{3}{4}+\frac{4}{4}$$

Since \frac{3}{4} and \frac{4}{4} have the same denominator, add them by adding their numerators.

$$\frac{3+4}{4}$$

Add 3 and 4 to get 7.

$$\frac{7}{4}$$

Factor

$$\frac{7}{2 ^ {2}} = 1\frac{3}{4} = 1.75$$