Solve sqrt[4]{(-64)*(-4)}+(-6)div12-left(5-4*3right)^2

$$\sqrt[ 4 ]{ (-64) \times (-4) } +(-6) \div 12- { \left(5-4 \times 3 \right) }^{ 2 }$$

Evaluate

$$-\frac{91}{2}=-45.5$$

Solution Steps

Multiply -64 and -4 to get 256.

$$\sqrt[4]{256}+\frac{-6}{12}-\left(5-4\times 3\right)^{2}$$

Calculate \sqrt[4]{256} and get 4.

$$4+\frac{-6}{12}-\left(5-4\times 3\right)^{2}$$

Reduce the fraction \frac{-6}{12} to lowest terms by extracting and canceling out 6.

$$4-\frac{1}{2}-\left(5-4\times 3\right)^{2}$$

Subtract \frac{1}{2} from 4 to get \frac{7}{2}.

$$\frac{7}{2}-\left(5-4\times 3\right)^{2}$$

Multiply 4 and 3 to get 12.

$$\frac{7}{2}-\left(5-12\right)^{2}$$

Subtract 12 from 5 to get -7.

$$\frac{7}{2}-\left(-7\right)^{2}$$

Calculate -7 to the power of 2 and get 49.

$$\frac{7}{2}-49$$

Subtract 49 from \frac{7}{2} to get -\frac{91}{2}.

$$-\frac{91}{2}$$

Factor

$$-\frac{91}{2} = -45\frac{1}{2} = -45.5$$