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\sqrt[3]{180}+7\sqrt{5}-\sqrt{125}
Factor 245=7^{2}\times 5. Rewrite the square root of the product \sqrt{7^{2}\times 5} as the product of square roots \sqrt{7^{2}}\sqrt{5}. Take the square root of 7^{2}.
\sqrt[3]{180}+7\sqrt{5}-5\sqrt{5}
Factor 125=5^{2}\times 5. Rewrite the square root of the product \sqrt{5^{2}\times 5} as the product of square roots \sqrt{5^{2}}\sqrt{5}. Take the square root of 5^{2}.
\sqrt[3]{180}+2\sqrt{5}
Combine 7\sqrt{5} and -5\sqrt{5} to get 2\sqrt{5}.