Solve sqrt[3]{-1000}-sqrt{100}+sqrt[3]{0.001}+6

$$\sqrt[ 3 ] { - 1000 } - \sqrt { 100 } + \sqrt[ 3 ] { 0.001 } + 6$$

Evaluate

$$-13.9$$

Solution Steps

Calculate \sqrt[3]{-1000} and get -10.

$$-10-\sqrt{100}+\sqrt[3]{0.001}+6$$

Calculate the square root of 100 and get 10.

$$-10-10+\sqrt[3]{0.001}+6$$

Subtract 10 from -10 to get -20.

$$-20+\sqrt[3]{0.001}+6$$

Calculate \sqrt[3]{0.001} and get \frac{1}{10}.

$$-20+\frac{1}{10}+6$$

Add -20 and \frac{1}{10} to get -\frac{199}{10}.

$$-\frac{199}{10}+6$$

Add -\frac{199}{10} and 6 to get -\frac{139}{10}.

$$-\frac{139}{10}$$

Factor

$$-13.9$$