Solve sqrt[3]{2+1-3*2+28/25}=x5/3

$$\sqrt[ 3 ]{ \frac{ 2+1-3 \cdot 2+28 }{ 25 } } = x \frac{ 5 }{ 3 }$$

Solve for x

$$x=\frac{3}{5}=0.6$$

Steps for Solving Linear Equation

Add 2 and 1 to get 3.

$$\sqrt[3]{\frac{3-3\times 2+28}{25}}=x\times \frac{5}{3}$$

Multiply 3 and 2 to get 6.

$$\sqrt[3]{\frac{3-6+28}{25}}=x\times \frac{5}{3}$$

Subtract 6 from 3 to get -3.

$$\sqrt[3]{\frac{-3+28}{25}}=x\times \frac{5}{3}$$

Add -3 and 28 to get 25.

$$\sqrt[3]{\frac{25}{25}}=x\times \frac{5}{3}$$

Divide 25 by 25 to get 1.

$$\sqrt[3]{1}=x\times \frac{5}{3}$$

Calculate \sqrt[3]{1} and get 1.

$$1=x\times \frac{5}{3}$$

Swap sides so that all variable terms are on the left hand side.

$$x\times \frac{5}{3}=1$$

Multiply both sides by \frac{3}{5}, the reciprocal of \frac{5}{3}.

$$x=1\times \frac{3}{5}$$

Multiply 1 and \frac{3}{5} to get \frac{3}{5}.

$$x=\frac{3}{5}$$